2y^2+5y-7=

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Solution for 2y^2+5y-7= equation:


Simplifying
2y2 + 5y + -7 = 0

Reorder the terms:
-7 + 5y + 2y2 = 0

Solving
-7 + 5y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-7 + -2y)(1 + -1y) = 0

Subproblem 1

Set the factor '(-7 + -2y)' equal to zero and attempt to solve: Simplifying -7 + -2y = 0 Solving -7 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2y = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2y = 0 + 7 -2y = 0 + 7 Combine like terms: 0 + 7 = 7 -2y = 7 Divide each side by '-2'. y = -3.5 Simplifying y = -3.5

Subproblem 2

Set the factor '(1 + -1y)' equal to zero and attempt to solve: Simplifying 1 + -1y = 0 Solving 1 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1y = 0 + -1 -1y = 0 + -1 Combine like terms: 0 + -1 = -1 -1y = -1 Divide each side by '-1'. y = 1 Simplifying y = 1

Solution

y = {-3.5, 1}

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